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i have my physics exam tomorrow and i need help understanding this problem because i got this wrong on a previous test

Two concurrent forces are acting on a box with a mass of 50.0 kg. One force is 555 N acting at an angle of 140 degrees; the other force is 785 N at an angle of 200 degrees. What third force would have to be added to the situation to produce a state of equilibrium?

f= ma i guess... i didnt use it though

555sin(40)-785sin(20) >> V

-555cos(40)-785cos(20) >> H

then i square rooted V^2 + H^2

then i tan^-1(V/H)

and i got some negative funky number

## Homework Statement

Two concurrent forces are acting on a box with a mass of 50.0 kg. One force is 555 N acting at an angle of 140 degrees; the other force is 785 N at an angle of 200 degrees. What third force would have to be added to the situation to produce a state of equilibrium?

## Homework Equations

f= ma i guess... i didnt use it though

## The Attempt at a Solution

555sin(40)-785sin(20) >> V

-555cos(40)-785cos(20) >> H

then i square rooted V^2 + H^2

then i tan^-1(V/H)

and i got some negative funky number

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