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Can someone point me in the right direction

  1. Mar 16, 2005 #1
    Hello

    I have to simplify the following expression can anybody help me get started??

    [tex]\frac{\frac{-3xy^{-2}}{x-1}}{10(\frac{xy}{z^3})^{-2}}[/tex]

    Thanks

    P
     
  2. jcsd
  3. Mar 16, 2005 #2
    The first thing is to take care of the negative exponent, then divide the fractions (by multiplying by the reciprical).
     
  4. Mar 30, 2005 #3
    Sorry I miss typed the problem(I think hard to tell)
    [tex]\frac{\frac{-3xy^{-2}}{z^{-1}}}{10(\frac{xy}{z^3})^{-2}}[/tex]

    So this is what I have so far

    [tex]\frac{\frac{-3xz^{1}}{y^{2}}}{10(\frac{z^3}{xy})^{2}}[/tex]

    [tex]\frac{\frac{-3xz^{1}}{y^{2}}}{10(\frac{z^6}{x^2y^2})}[/tex]

    [tex]\frac{\frac{-3xz^{1}}{y^{2}}}{(\frac{10z^6}{10x^2y^2})}[/tex]

    [tex]{\frac{-3xz^{1}}{y^{2}}}X{\frac{10x^2y^2}{10z^6}[/tex]

    Am I on the right track?
     
  5. Mar 30, 2005 #4
    yeah except one thing:
    when you multiply the faction by 10, it only goes on the top, not on the bottom. So then when you invert it, its going to be on the botton
    (x^2)(y^2) / (10 z^6)
    the rest is fine now u just need to cancel the y^2 and the z
     
  6. Mar 30, 2005 #5
    so it is ?

    [tex]{\frac{-3xz^{1}}{y^{2}}}X{\frac{x^2y^2}{10z^6}[/tex]

    how do the z cancel each other out?
     
  7. Mar 30, 2005 #6

    dextercioby

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    They don't

    [tex] \frac{-3}{10}\frac{x^{3}}{z^{5}} [/tex]


    Daniel.
     
  8. Mar 30, 2005 #7
    does it work out like this??

    [tex]{\frac{-3x^3y^2z^1}{10y^{2}z^6}}[/tex]

    [tex]{\frac{-3x^3y^{2-2}z^{1-6}}{10}}[/tex]

    [tex]{\frac{-3x^3y^{0}z^{-5}}{10}}[/tex]

    [tex]{\frac{-3x^3}{10z^{5}}}[/tex]
     
  9. Mar 30, 2005 #8

    dextercioby

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    Exactly like that.

    Daniel.
     
  10. Mar 30, 2005 #9
    Thanks for you help
     
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