# Can someone prove this to me

1. Apr 28, 2006

### Miss_lolitta

Hello,
can someone prove this to me as.
Any help would help save my hair I have not torn out as yet.

If $a_n,b_n$are sequences of real number ,n>m then:

$a_{n+1}S_n-a_m S_{m-1}+\sum_{k=m}^{n}( a_k - b_{k+1})S_k$
Where $S_n$is the partial sum of sequence $\sum_{k=1}^{\infty}b_n$

Thanks for any help

2. Apr 28, 2006

### matt grime

the tag here is tex, not math, in the square brackets.

If $$a_n,b_n$$
are sequences of real number ,n>m then:

$$a_{n+1}S_n-a_m S_{m-1}+\sum_{k=m}^{n}( a_k - b_{k+1})S_k$$
Where $$S_n$$is the partial sum of sequence $$\sum_{k=1}^{\infty}b_n$$

nope, still makes no sense.

3. Apr 28, 2006

### Miss_lolitta

yes that's right

thanks

4. Apr 28, 2006

### mathwonk

what color is your hair?

5. Apr 29, 2006

### Miss_lolitta

silver:rofl:

6. Apr 29, 2006

### HallsofIvy

Staff Emeritus
equals what??
Presumably you mean "Where $$S_n$$is the partial sum of sequence
$$\sum_{k=1}^n b_n$$

7. Apr 29, 2006

### Miss_lolitta

sorry

$$\sum_{k=1}^n (a_k . b_k)$$=$$a_{n+1}S_n-a_m S_{m-1}+\sum_{k=m}^{n}( a_k - b_{k+1})S_k$$

Last edited: Apr 29, 2006