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Can someone prove this to me

  1. Apr 28, 2006 #1
    Hello,
    can someone prove this to me as.
    Any help would help save my hair I have not torn out as yet.:cry:

    If [math]
    a_n,b_n
    [/math]are sequences of real number ,n>m then:

    [math]
    a_{n+1}S_n-a_m S_{m-1}+\sum_{k=m}^{n}( a_k - b_{k+1})S_k
    [/math]
    Where [math]
    S_n
    [/math]is the partial sum of sequence [math]
    \sum_{k=1}^{\infty}b_n
    [/math]

    Thanks for any help
     
  2. jcsd
  3. Apr 28, 2006 #2

    matt grime

    User Avatar
    Science Advisor
    Homework Helper

    the tag here is tex, not math, in the square brackets.

    If [tex]
    a_n,b_n
    [/tex]
    are sequences of real number ,n>m then:

    [tex]
    a_{n+1}S_n-a_m S_{m-1}+\sum_{k=m}^{n}( a_k - b_{k+1})S_k
    [/tex]
    Where [tex]
    S_n
    [/tex]is the partial sum of sequence [tex]
    \sum_{k=1}^{\infty}b_n
    [/tex]

    nope, still makes no sense.
     
  4. Apr 28, 2006 #3
    yes that's right

    thanks
     
  5. Apr 28, 2006 #4

    mathwonk

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    Science Advisor
    Homework Helper
    2015 Award

    what color is your hair?
     
  6. Apr 29, 2006 #5
    silver:rofl:
     
  7. Apr 29, 2006 #6

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    equals what??
    Presumably you mean "Where [tex]
    S_n
    [/tex]is the partial sum of sequence
    [tex]\sum_{k=1}^n b_n[/tex]
     
  8. Apr 29, 2006 #7
    sorry

    [tex]\sum_{k=1}^n (a_k . b_k)[/tex]=[tex]a_{n+1}S_n-a_m S_{m-1}+\sum_{k=m}^{n}( a_k - b_{k+1})S_k[/tex]
     
    Last edited: Apr 29, 2006
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