ok, i know that 205 can be written as the following: (205/n)=(5/n)(41/n), which reduces to =(-1)(-1)=1. so there are either 2 cases for this problem, (5/n)=1 or (41/n)=1.
that is possibly correct in spirit, but needs better explanation: at least one of 5,41 or 41*205 must be a quadratic residue mod n for each n because...