# Can the summation.

Can the summation.......

Can the summation of a number equal that numbers square root??

arildno
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How can you sum a single number?

NateTG
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Well, I think that
$$\sqrt{1}=1$$
and
$$\sqrt{0}=0$$
both work...

arildno
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whatzzupboy:
Did you mean something like this:
Has the following equation any solutions:
$$x+x=\sqrt{x}$$ ?

dextercioby
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There's something weird-------->fishy here,so let's see whether he can ask a logically valid question... Daniel.

for example:
<sum> of x^y
can it equal the square root of y

Last edited:
dextercioby
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What's the variable you sum after and what possible values can it take...?

Daniel.

any im just asking though is there any way at all that the summation of a number equal its square root

dextercioby
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It still doesn't make any sense,sorry...Are u referring to a power/geometric series...?

Daniel.

no i'm saying if u take the summation of any number can its factors equal the numbers square root

Summation notain of x^1 to (x-1)^1= 1^1+2^1+3^1+4^1......(x-1)^1

dextercioby
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You mean something like:
$$\sum_{k=1}^{n} k^{power}$$

If the sum streches to infinity,then there could be made a connection to the zeta-Riemann function...

Daniel.

Galileo
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dextercioby said:
If the sum streches to infinity,then there could be made a connection to the zeta-Riemann function...

Whatzzupdude, please try to explain what you exactly mean by 'summation of a number'.

arildno
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whatzzupboy said:
no i'm saying if u take the summation of any number can its factors equal the numbers square root

Summation notain of x^1 to (x-1)^1= 1^1+2^1+3^1+4^1......(x-1)^1
This is the sum of of the first (x-1) integers; it is not a summation "notain" (whatever that is) of x^1 to (x-1)^1.

dextercioby said:
You mean something like:
$$\sum_{k=1}^{n} k^{power}$$

If the sum streches to infinity,then there could be made a connection to the zeta-Riemann function...

Daniel.

Thank you Dextercioby, that is exactly what I meant can
$$\sum_{k=1}^{n} k^{power}$$
equal the root of n

i think that he means

x^y=x + y?

if so than 2^2= 2+2......but I seirously doubt thats what you mean

why dont you add the definition summation into the glossary :)

$$\sum_{k=1}^n k^a = \sqrt{n}$$

for some constants a and n?

--J

yes that is exactly what i mean

NateTG
$$\sum_{k=1}^1 1^1 = \sqrt{1}$$