Can You All Tell Me How To Do This Step By Step.

  • Thread starter Chikawakajones
  • Start date
In summary: In this case, the squares are 2 cm on a side, so their areas are 4 cm^2 and 196 cm^2. So the length of the segment joining the centers of the inscribed circles is 4 cm.
  • #1
Chikawakajones
22
0
:confused: The Areas Of 2 Adjacent Squares Are 4 cm^2 and 196 cm^2.

Find The Length Of The Segment Joining The Centers Of Their Inscribe Circles.

(Theres A Picture Of 1 Big Square And 1 Small Square - Each Square Has A Circle Inside - The Center Of Each Circle Is Indicated By A Dot - There Is One Line Connecting The 2 Dots.)

( I Don't Know How To Post The Picture In Here)
 
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  • #2
well, the first square is 2x2 (you just get the square root) and the 2nd square is 14x14 so...
the radius of the first circle is 1 (it's half the diameter) and the 2nd one is 7 so...?

7+1 = 8
 
  • #3
futb0l said:
well, the first square is 2x2 (you just get the square root) and the 2nd square is 14x14 so...
the radius of the first circle is 1 (it's half the diameter) and the 2nd one is 7 so...?

7+1 = 8

Since this is a geometry problem without a picture and with an ambiguous text (u cannot tell only by looking at the text how those squares are),text it is quite a big probability that uyour answer to be wrong. :wink:

Daniel.

PS.Did u try to put as an attachement to your message?It usually works that way,as long as it's not more than 50kB of data.
 
  • #4
dextercioby said:
Since this is a geometry problem without a picture and with an ambiguous text (u cannot tell only by looking at the text how those squares are),text it is quite a big probability that uyour answer to be wrong. :wink:

Daniel.

PS.Did u try to put as an attachement to your message?It usually works that way,as long as it's not more than 50kB of data.

You're right Dan - My name is also Daniel too, btw :tongue: ...
I don't know what he meant by "adjacent" - I just assume the simplest case.
 

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