# Can you check if it is right?

1. Sep 23, 2007

### yaho8888

1. The problem statement, all variables and given/known data
Find the area of $$y= \frac{1}{\cos^2 x}$$ from $$x=0$$ to $$x = \frac{\pi}{2}$$.

2. The attempt at a solution

$$\int \frac{1}{\cos^2 x}$$ from 0 to $$\frac{\pi}{2}$$.
equals $$\tan x$$
and take the limit from the negative side of $$\frac{\pi}{2}$$.
since limit of tan at $$\frac{\pi}{2}$$ is $$\infty$$
the funtion is divergent.
so the area dosen't exist.

Last edited: Sep 23, 2007
2. Sep 23, 2007

### yaho8888

I was wondering why no one answer this forum, you only have to check if I am right( yes or no).

3. Sep 23, 2007

### neutrino

The integral is divergent.

4. Sep 23, 2007

### learningphysics

Yes, you are right.