A baseball pitcher throws a fast-ball (mass 50g) to stop a bullet (mass 5g), which has been shot at him at a speed of 400m/s by an angry fan. Can the pitcher save himself by stopping the bullet with a fast-ball of 100mph assuming a perfectly inelastic head-on collision, where the bullet gets stuck in the baseball?
What is the final momentum and the final speed of the baseball+bullet system?
P = mv+mv
The Attempt at a Solution
So I did:
P= bullet = (400m/s)(0.005kg) = 2
p = fast-ball = 100mph = 44.7m/s = (44.7m/s)(0.05kg) = 2.235
Pf = 2.235 + 2 = 4.235kg.m/s
If the question were find the final velocity of the bullet, I guess I´d have written 0, right (because it´s perfectly inelastic)?
But since I am being asked the final speed for both baseball +bullet system, I am attempting:
v = p/m
v = 4.235kg.m/s divided by 0.055kg (total mass) = 77m/s.
So, is that correct?