Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Can you help me out on #1? It's a hard question.

  1. Jul 12, 2004 #1
    Last edited: Jul 13, 2004
  2. jcsd
  3. Jul 13, 2004 #2
    Still haven't figured it out. Does anyone have an idea?
  4. Jul 13, 2004 #3
    Has no one else figured this out yet? :surprise:

    There must be an answer! Someone, please help!
  5. Jul 14, 2004 #4
    There are 2 groups with 10 balls and one group with 20 balls (once you find the missing 4). In the group of 20 look at the first ball at the top and the first ball at the bottom (pink and blue), match that with a pink and blue (same positions) in the first group of 10.

    Then go to the next two balls in the group of 20 and match them with the second group of 10.

    Keep alternating until you eliminate all but the last 4, use these to complete the problem.
  6. Jul 14, 2004 #5
    Thanks!!! I would of never guessed that.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook