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jo3jo3520
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Im having a bit of trouble understanding this and hoping someone can give me an idea how to understand and calculate net displacement of 3 different directions and distances?
jo3jo3520 said:Im assuminh your going to tell me on so now we have 90m North and then 50 East. so then take 90^2 + 50^2 and you get your answer for the net displacement>?
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jo3jo3520 said:and 52^2 + 30^2=3604^2 and the SR = 60 ...so the height of the tree is 30m?
Net displacement is the overall change in an object's position from its starting point to its ending point. It takes into account both the distance and direction of the object's movement.
Net displacement is calculated by finding the difference between an object's final position and its initial position. This can be done by subtracting the initial position vector from the final position vector.
Net displacement and total distance are both measures of an object's movement, but they differ in how they are calculated. Net displacement takes into account the object's final position, while total distance considers the distance traveled along the entire path.
Net displacement is important in physics because it helps us understand an object's overall movement and its final position. It is also used in calculating other important quantities such as velocity and acceleration.
Yes, net displacement can be negative. This indicates that the object has moved in the opposite direction of its initial position. A positive net displacement means the object has moved in the same direction as its initial position.