- #1
mad
- 65
- 0
Hello, I just wanted to know if you can integrate a vector, and if so, how.
Here is a problem: A charged piece of metal of linear density 2 * 10^-6 * x , between x=2 and x=5.
I found its charge by integrating.. and it is 21 micro C.
Now that's what I want to know: calculate the electric field at x=0
I know that [tex] \vec{E} = \int{} d \vec{E} [/tex]
but in my physics book, it says I have to decompose it in [tex] E_x [/tex] or [tex] {E_y}[/tex] and integrate. But since I hate working without vectors, do you think there's a way to integrate without decomposing it in x and y, like something like this..:
[tex] \vec{E} = \int{} \frac{k dq }{r^2} \vec{u}[/tex] = [tex] \vec{E} = \int{} \frac{k \lambda dx }{x^2} \vec{u}[/tex]
Is there a way to do this? My teacher hasn't started this topic yet, I'm just curious.
Thanks a lot !
Here is a problem: A charged piece of metal of linear density 2 * 10^-6 * x , between x=2 and x=5.
I found its charge by integrating.. and it is 21 micro C.
Now that's what I want to know: calculate the electric field at x=0
I know that [tex] \vec{E} = \int{} d \vec{E} [/tex]
but in my physics book, it says I have to decompose it in [tex] E_x [/tex] or [tex] {E_y}[/tex] and integrate. But since I hate working without vectors, do you think there's a way to integrate without decomposing it in x and y, like something like this..:
[tex] \vec{E} = \int{} \frac{k dq }{r^2} \vec{u}[/tex] = [tex] \vec{E} = \int{} \frac{k \lambda dx }{x^2} \vec{u}[/tex]
Is there a way to do this? My teacher hasn't started this topic yet, I'm just curious.
Thanks a lot !
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