this example is being discussed by our professor in our class ! ( the one that i upload is the illustration made by our prof in our class ) this are the given and the solution : A=2.0m @ 40' B=4.0m @127' SOLUTION : R^2=A^2+B^2– 2AB Cos93' R^2=(2.0)^2 + (4.0)^2 -(2)(2)(4)cos93' R=4.56m sinθ/4=sin93'/4.56 sinθ=62.2' 11.2 west of north guys ! please explain to me how did they get the sinθ=62.2' and 11.2 west of north and the formula ! thanks ! if u answer this i can now make the assignment given by our prof thanks a lot !