- #1

Gregory

- 2

- 0

I have a problem, and I have no clue where to start- anyone have any help?

Any help would be very appreciated... I am using the formula p=mv and p(A1)=P(1)sin x (The (A1) and (1) are subscripts)

I figured out that

P(A) = (v*925kg)*(sin x) (again, (A) is a subscript of p)

P(A) = (v*1265kg)*(cos x) (again, (A) is a subscript of p)

but, I'm not sure if that's even correct..

I was hoping F(f)=uF(N) would be useful, as its the only forumula I could find that uses the coefficient of friction (The (f) and (N) are subscripts, the "u" stands for the coefficient of friction- I couldn't find the right symbol for it)

I have a few diagrams drawn, but other than that, I couldn't figure out how to start...

Your friend has been in a car accident and wants your help. She was driving her 1265-kg car north on Oak Street when she was hit by a 925-kg compact car going wast on Maple Street. The cars stuck together and slid 23.1m at 42° north of west. The speed limit on both streets is 50 mph (22 m/s). Your friend claims that she wasn't speeding, but that the other car was. Can you support her case in court? Assume that momentum was conserved during the collision and that acceleration was constant during the skid. The coefficient of kinetic friction between the tires and the pavement is 0.65.

Any help would be very appreciated... I am using the formula p=mv and p(A1)=P(1)sin x (The (A1) and (1) are subscripts)

I figured out that

__Car 1 (Westward)__P(A) = (v*925kg)*(sin x) (again, (A) is a subscript of p)

__Car 1 (Northward)__P(A) = (v*1265kg)*(cos x) (again, (A) is a subscript of p)

but, I'm not sure if that's even correct..

I was hoping F(f)=uF(N) would be useful, as its the only forumula I could find that uses the coefficient of friction (The (f) and (N) are subscripts, the "u" stands for the coefficient of friction- I couldn't find the right symbol for it)

I have a few diagrams drawn, but other than that, I couldn't figure out how to start...

Last edited: