Cannibals brain teaser

  • Thread starter cefarix
  • Start date
  • #1
cefarix
78
0
There's a boat to cross a river, and it can carry 2 people at once. There are 3 cannibals and 3, well, regular people on one side of the river. They want to get across. If there are more cannibals on one side than regular people, you lose. The boat cannot travel empty.
Have fun! :biggrin:
 

Answers and Replies

  • #2
NateTG
Science Advisor
Homework Helper
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Two canibals cross.
One cannibal takes the boat back.
Two cannibals cross.
One takes the boat back.
Two non-cannibals cross.
A cannibal and a non-cannibal take the boat back.
Two non-cannibals cross.
A cannibal takes the boat back.
Two cannibals cross.
A cannibal takes the boat back
Two cannibals cross.
 
  • #3
cefarix
78
0
sorry, should've mentioned that cannibals cannot pilot the boat
 
  • #4
BTruesdell07
17
0
Answers

Get another boat.
Swim.

Can there be a canable on a side when no one else is there or do they start to eat them selves?
 
  • #5
LarrrSDonald
71
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I must misunderstand the rules somehow..

C=Canibal c=Non-canibal

Initially, one C one c must cross. If two or one c cross the remaining will be eaten and zero c isn't an option (no one to use the boat). From there on, the c has to return (if he brought the C that'd be back to square one and nothing else is possible). One c from there would be back to previous state, two c would get the remaining c eaten and one c one C would get the traveling c eaten upon arival at the other side (which would then be two C one c). Unless we're talking some sort of wordplay like the one c staying in the boat with two C on the shore or something to that effect, it's impossible.
 
  • #6
cefarix
78
0
LarrrSDonald said:
I must misunderstand the rules somehow..

C=Canibal c=Non-canibal

Initially, one C one c must cross. If two or one c cross the remaining will be eaten and zero c isn't an option (no one to use the boat). From there on, the c has to return (if he brought the C that'd be back to square one and nothing else is possible). One c from there would be back to previous state, two c would get the remaining c eaten and one c one C would get the traveling c eaten upon arival at the other side (which would then be two C one c). Unless we're talking some sort of wordplay like the one c staying in the boat with two C on the shore or something to that effect, it's impossible.

Your answer is indeed correct. Congratulations. :approve:
 
  • #7
ckrishanu
1
0
hi friends, make the cannibal problem a little complicated. suppose, all the regular men can row the boat. and one out of three canibals can row the boat. the story remains same. now try!!

kris
 
  • #8
NateTG
Science Advisor
Homework Helper
2,452
6
ckrishanu said:
hi friends, make the cannibal problem a little complicated. suppose, all the regular men can row the boat. and one out of three canibals can row the boat. the story remains same. now try!!


ccCMMM.|
cMMM |.cC
cCMMM.|c
MMM |.ccC
CMMM.| cc
CM |. ccMM
CcMM.| cM
cM |. cCMM
ccMM.| CM
cc |.CMMM
ccC.| MMM
c |. cCMMM
cC.| cMMM
|.ccCMMM
 
  • #9
Tzar
74
0
Here is a brain teaser: What do i need to do to start my onw threads??? I can't work it out. PLEASE help.
 
  • #10
gerben
510
1
Tzar said:
Here is a brain teaser: What do i need to do to start my onw threads??? I can't work it out. PLEASE help.

click on the green "new thread" button
 
  • #11
Tzar
74
0
Cheers, I'm such an idiot for not seeing it...
 
  • #12
coffee na lang dear
25
0
maybe i can help them solve thru visuals via this link: http://www.plastelina.net/games/game1.html

the logic game is called Cannibals and Missionaries :)
 

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