Your answer is indeed correct. Congratulations.LarrrSDonald said:I must misunderstand the rules somehow..
Initially, one C one c must cross. If two or one c cross the remaining will be eaten and zero c isn't an option (no one to use the boat). From there on, the c has to return (if he brought the C that'd be back to square one and nothing else is possible). One c from there would be back to previous state, two c would get the remaining c eaten and one c one C would get the traveling c eaten upon arival at the other side (which would then be two C one c). Unless we're talking some sort of wordplay like the one c staying in the boat with two C on the shore or something to that effect, it's impossible.
ckrishanu said:hi friends, make the cannibal problem a little complicated. suppose, all the regular men can row the boat. and one out of three canibals can row the boat. the story remains same. now try!!