A connon, located 60 m from the base of a vertical 25.0m tall clift, shoots a 15 kg shell at 43.0 degrees above the horizontal toward the cliff. A) what must the minimum muzzle velocity be for the shell to clear the top of the cliff? B) The ground at the top of the cliff is level, with a constant elevation of 25.0 m above the cannon. Under the conditions of part (A), how far does the shell past the edge of the cliff? x=x0 + V0t Vy= v0y-gt y=y0+v0yt-1/2gt^2 vf^2=vi^2-2ax I am a little throw off by the kg of the shell. I do not know how to start the prob.