A connon, located 60 m from the base of a vertical 25.0m tall clift, shoots a 15 kg shell at 43.0 degrees above the horizontal toward the cliff.(adsbygoogle = window.adsbygoogle || []).push({});

A) what must the minimum muzzle velocity be for the shell to clear the top of the cliff?

B) The ground at the top of the cliff is level, with a constant elevation of 25.0 m above the cannon. Under the conditions of part (A), how far does the shell past the edge of the cliff?

x=x0 + V0t

Vy= v0y-gt

y=y0+v0yt-1/2gt^2

vf^2=vi^2-2ax

I am a little throw off by the kg of the shell. I do not know how to start the prob.

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# Homework Help: Cannon hits cliff

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