A daredevil is shot out of a cannon at 24.0° to the horizontal with an initial speed of 26.0 m/s. A net is positioned a horizontal distance of 50.0 m from the cannon. At what height above the cannon should the net be placed in order to catch the daredevil?(adsbygoogle = window.adsbygoogle || []).push({});

Ok, here's how the teacher explained it.

Vx = Vcos(theta)

Vy=Vsin(theta)

t = (horizontal distance) / Vx

and finally y = VyT + .5gt^2

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So, here's the work.

Vx = 23.75

Vy = 10.575

t = 2.105

y = (10.575)(2.105) + .5(-9.8)(2.105)^2

= .54797 m

Help me :surprised

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# Cannon projectile motion problem

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