A cannon has a launch speed of 500m/s and is aimed at a target 2.8km away.
a. Write an equation for the maximum horizontal range of the cannon as a function of the launch angle theta.
b. At what angle must the cannon be launched in order to hit the target?
c. As viewed from above, how quickly does the cannonball's shadow move along the ground?
d. How fast is the cannonball moving when it hits its target?
D = vit+1/2at^2
Range of a projectile
The Attempt at a Solution
a. I used the range of a projectile motion and got v^2sin2(theta)/g but I dont know how to make it a function of the launch angle theta. Am I overreading?
b. Im assuming you just plug in the values from the first formula you get.
c. Just find the acceleration?
d. Just find the vf?