Cannonball Question Solved - 200m Target Hit?

  • Thread starter juliany
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In summary, the problem involves a 3 tonne cannon firing a 20kg cannonball at a speed of 250m/s towards a target 200 metres away. The cannon is 1 metre above ground level. The first part of the problem can be solved using conservation of momentum, while the second part is a kinematics problem that can be solved by determining the time for the cannonball to hit the target and the ground using the given initial velocity and assuming no air resistance.
  • #1
juliany
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Solved!

Homework Statement


A 3 tonne cannon fires a 20kg cannonball horizontally at a speed of 250m/s at a target 200 metres away. The cannon is 1 metre above ground level
a. Determine the recoil velocity of the cannon.
b. Assuming the cannon is wel aimed, will the cannon ball hit the target before it strikes the ground?


Homework Equations


a. I am unsure about this one, but would you determine the force of the cannon firing the cannonball and incorporate Newton's third law?

b. Would you determine the time for the cannonball to hit the target and the time for it to hit the ground? I am unsure which equation to use for this one as well:confused:



The Attempt at a Solution


Kind of answered this is relevant equations:blushing:
 
Last edited:
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  • #2
The first part uses conservation of momentum. There are no forces involved because the velocity is constant.

Anything related to mass (including force) is unnecessary for the second part as it is just a kinematics problem. You're already given initial velocity [tex]v_{0x}=250\frac{m}{s}[/tex] and [tex]v_{0y}=0\frac{m}{s}[/tex]. If you're assuming there's no air resistance, then [tex]v_{0x}[/tex] is constant so [tex]x(t)=v_{0x}t[/tex] and [tex]y(t)=-\frac{g}{2}t^{2}+v_{0y}t+y_{0}[/tex].
 
  • #3
zcd said:
The first part uses conservation of momentum. There are no forces involved because the velocity is constant.

Anything related to mass (including force) is unnecessary for the second part as it is just a kinematics problem. You're already given initial velocity [tex]v_{0x}=250\frac{m}{s}[/tex] and [tex]v_{0y}=0\frac{m}{s}[/tex]. If you're assuming there's no air resistance, then [tex]v_{0x}[/tex] is constant so [tex]x(t)=v_{0x}t[/tex] and [tex]y(t)=-\frac{g}{2}t^{2}+v_{0y}t+y_{0}[/tex].

Thanks:smile:
 

1. What is the "Cannonball Question Solved - 200m Target Hit"?

The "Cannonball Question Solved - 200m Target Hit" refers to a scientific experiment or calculation that has successfully determined the trajectory and impact point of a cannonball fired at a distance of 200 meters.

2. How was the "Cannonball Question Solved - 200m Target Hit" achieved?

The "Cannonball Question Solved - 200m Target Hit" was likely achieved through a combination of mathematical calculations, physical principles, and experimental data. Scientists may have used equations such as projectile motion or air resistance to determine the trajectory of the cannonball, and then verified their calculations through experiments.

3. What is the significance of the "Cannonball Question Solved - 200m Target Hit"?

The "Cannonball Question Solved - 200m Target Hit" is significant because it demonstrates the ability of scientists to predict and control the movement of objects through the application of scientific principles. It also has practical applications, such as in military strategy or engineering design.

4. What factors may have influenced the accuracy of the "Cannonball Question Solved - 200m Target Hit"?

There are several factors that could have influenced the accuracy of the "Cannonball Question Solved - 200m Target Hit", such as air resistance, wind speed and direction, the shape and weight of the cannonball, and the angle and force of the cannon's firing. Other factors, such as human error in measurements or calculations, could also play a role.

5. Are there any real-world examples of the "Cannonball Question Solved - 200m Target Hit"?

Yes, there are many real-world examples of the principles behind the "Cannonball Question Solved - 200m Target Hit". For instance, engineers may use similar calculations to design projectiles for military or industrial purposes. Additionally, understanding the physics of projectile motion is crucial in sports such as archery or javelin throwing.

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