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Can't figure this out

  1. Sep 1, 2004 #1


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    A particle moves in the x-y plane with constant acceleration. At time t = 0 s, the position vector for the particle is d = 2.2 m x + 8.2 m y. The acceleration is given by the vector a = 4.5 m/s2 x + 2.2 m/s2 y. The velocity vector at time t = 0 s is v = 3.3 m/s x - 4.3 m/s y. Find the magnitude of the velocity vector at time t = 8.3 s.

    I never liked vectors :mad:
  2. jcsd
  3. Sep 1, 2004 #2


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    No man. Change that attitude. Vectors are like, totally awesome :cool:
    You'll appreciate them when you take linear algebra.

    Anyway, simply view this problem as two one-dimensional problems.
    The x- and y coordinates are independent.
    Since the acceleration is constant, the formula for the speed as a function of time is:
    And a similar equation for [itex]v_y(t)[/itex].

    You can calculate
    with this.
  4. Sep 1, 2004 #3


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    Dearly Missed

    No, they start rocking when taking physics :wink:
  5. Sep 1, 2004 #4


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    U guys are right

    Vectors don"t suck. I think I was just frustrated with the rest of my work.

    I am taking physics and that was a physics problem.

    Any ways I got all the answers right on CAPA, so everything rocks!!! :tongue:

    Time to :zzz: :zzz:
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