A particle moves in the x-y plane with constant acceleration. At time t = 0 s, the position vector for the particle is d = 2.2 m x + 8.2 m y. The acceleration is given by the vector a = 4.5 m/s2 x + 2.2 m/s2 y. The velocity vector at time t = 0 s is v = 3.3 m/s x - 4.3 m/s y. Find the magnitude of the velocity vector at time t = 8.3 s.(adsbygoogle = window.adsbygoogle || []).push({});

I never liked vectors

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# Homework Help: Can't figure this out

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