- #1

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**can't get this!!!**

Hi there,

I have a question that I cannot solve. Here it is.

[tex]\frac{1}{\sqrt(4-2\sqrt3)}=x+y\sqrt3 [/tex]

then what is x^2+y^2?

All I did was finding what left hand side stood for. It equals

[tex]\frac{\sqrt3 + 1}{2} [/tex]

Any help?