- #1
fatboy12341
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in a rutherford gold experiment, alpha particles with sharge +2e and a kinetic energy of 7.7 Mev were beamed at gold foil. the nuclius of a gold atom contains 79 protons, giving it a charge of +79e. What is the closest distance that an alpha particle can get to a gold nucleus when it approaches head on ?
ok i used the equation En=k^2 x e^4 me . Z^2
2xh^2 h^2
i am getting n^2= -9.07x10^21
i know this is wrong and am getting quite frustrated
if some on could help me it would be great
ok i used the equation En=k^2 x e^4 me . Z^2
2xh^2 h^2
i am getting n^2= -9.07x10^21
i know this is wrong and am getting quite frustrated
if some on could help me it would be great