- #1

shirozack

- 18

- 3

- Homework Statement
- See attach

- Relevant Equations
- none

I can find the area of e and f but otherwise am stuck with many simultaneous equations. i don't think my approach is correct though considering it is an elementary school problem. it should be simpler?

1 semicircle area = π(52)/2 = 12.5π = 39.25 cm2

Square area = 10x10 = 100cm2

Square – 2 semicircle = 2 edge = 21.5, so 1 edge = 10.75

so 2 e + edge = semicircle

e = (39.25 – 10.75) / 2 = 14.25 cm2

so f = 39.25 – 14.25 = 25 cm2

area of quad = 1/4 * pi * 102 = 25pi = 78.5 cm2

c+d = quad – (e+f) = 39.25 cm2

b+c = semi – e = 25cm2

also, 39.25 – c = b+e = b + 14.25

so c = 25 - b

get rid of c by setting them equal so, 39.25 – d = 25 - b

so d = 14.25 + b

a + b + quad = square

a + b =21.5 cm2

a+d + b+c+e+f = square

a+d +64.25 = 100, a+d = 35.75

sub d in, a+14.25+b = 35.75, so a+b =