Could someone help me and write an algorithm to add 2 Cantor expansions. The algorithm to get a decimal number to cantor expansion is: procedure decimal-to-cantor(x: positive integer) n := 1 y := x fy is a temporary variable used so that this procedure won't destroy the original value of x.g while y 6= 0 begin an := y mod (n+1) y := (y-an )/(n+1) n := n + 1 end f The expansion for x will be an n! + an−1 (n-1)! + : : : + a22! + a1 . g Now i just need to figure out how to add 2 cantor expansion numbers together to get one. Someone help please!