Capacitance and Inductance.

  • Thread starter airkapp
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  • #1
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The variable capacitor in the tuner of an AM radio has capacitance of 1800pF when the radio is tuned to a station at 550 kHz. a) What must be the capacitance for a station at 1600 kHz?

I found the frequency first and then am I supposed to setup the 1600 equal to the frequency to find the capitance.

f = f = w / 2π = 1 / (2 π √ LC )

550000 Hz = 1 / (2 π √L * 1.8E-9 Hz)

= H

Do I just use algebra to isolate for L and then use my new inductance to my find my new C.

Am I going to need to use my period? None of these methods seem to be working..
T = 1/f

thanks
air
 
Last edited:

Answers and Replies

  • #2
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airkapp said:
Do I just use algebra to isolate for L and then use my new inductance to my find my new C.
This is what I would do given the information.

What are you getting? What is the right answer I am getting. [itex]2.12*10^{-4}\ F[/itex]
 

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