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Introductory Physics Homework Help
Capacitance capacitor parallel plate with dielectric (Gauss)
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[QUOTE="Ark236, post: 5756289, member: 599389"] [h2]Homework Statement [/h2] I have an elementary doubt with the calculation of the capacitance of a capacitor of parallel plates that has a dielectric in the middle. [PLAIN]https://ibb.co/b0W4BQ[/PLAIN] [h2]Homework Equations[/h2] ∫D⋅ds=Q D=E+γP C=Q/V [h2]The Attempt at a Solution[/h2] Suppose the top plate has a positive charge and the bottom plate has a negative charge. To calculate vector displacement in the upper plate, we occupy the gauss law, use a Gaussian box. On the outside of the top plate the polarization P is 0 and there is an electric field E. At the bottom of the plate there is an electric field E and a polarization P due to the dielectric. If we consider only the top plate: ∫D⋅ds=[D][/out]A+[D][/down]A=Q [D][/out]=E [D][/down]=E+γP If we consider the complete system[B] ([/B]both plates[B]) [/B] ∫D⋅ds=2*[D][/out]A+2*[D][/down]A=Q [D][/out]=E [D][/down]=E+γP The field inside is 2 E. What is the error, I do not understand. D is zero outside from capacitor? Thank you [/QUOTE]
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Introductory Physics Homework Help
Capacitance capacitor parallel plate with dielectric (Gauss)
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