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ColliLJ
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I would like to understand why my 100uF 6.3V X5R dielectric ceramic capacitor decreases to ~60uF under a 5V applied DC bias. Can anyone explain the physical phenomenon?
Capacitance decrease with applied DC refers to the phenomenon in which the capacitance of a capacitor decreases when a direct current (DC) voltage is applied to it. This is due to the accumulation of charge on the capacitor plates, which creates an electric field that opposes the applied voltage and reduces the effective capacitance.
Capacitance decreases with applied DC because as charge accumulates on the capacitor plates, an electric field is created that opposes the applied voltage. This opposing electric field reduces the effective capacitance of the capacitor, as it makes it more difficult for the capacitor to store additional charge.
The decrease in capacitance can affect circuit performance in a few ways. One of the main effects is a decrease in the overall capacitance of the circuit, which can alter the circuit's ability to store and release electrical energy. This can also lead to changes in the circuit's frequency response and time constant.
Yes, capacitance decrease with applied DC can be reversed by removing the applied voltage. This allows the accumulated charge on the capacitor plates to dissipate and the electric field to disappear, resulting in the original capacitance being restored.
Capacitance decrease with applied DC can be measured using a capacitance meter. This device applies a known voltage to the capacitor and measures the resulting capacitance. By comparing the measured capacitance to the original value, the decrease in capacitance can be determined.