1. The problem statement, all variables and given/known data http://loncapa2.fsu.edu/enc/66/45d3639022485d2ba995cf84c579b584bffe5ace9851f3da3fbac5f5a1c7d2ee9dfed8743cf75459ef336ad7a1bbe176f7a0cf1a35a519ce0cef3c31febf9858404cac5a2cd3ace3851dbef61ee03a25f7a5c41a87b32e0f.gif Calculate the equivalence capacitance of the circuit shown in the diagram above; where C1 = 8.65 μF, C2 = 4.00 μF, C3 = 8.55 μF, C4 = 3.20 μF. 2. Relevant equations Capacitance in a series: 1/Ctot = Ʃ(1/C) Capacitance in parallel: Ctot = ƩC 3. The attempt at a solution Well, I attempted multiple ways to order each capacitor into a way to solve a formula. In my sixth attempt I presumed that C1 and C2 are in a series and are parallel to C3. I also believe C4 is parallel to C3, so here is my equation: C = (1/C1 + 1/C2) + C3 + C4 Another idea that came into ferment was the concept of thinking that C2 and C3 are in series and are parallel to C1. C4 would be parallel to C2 and C3 so: C = C1 + (1/C2 + 1/C3) + C4 I could go on, but since my professor never went over this I am thoroughly confused.