Hi all, I have been looking at this problem for a while now and can not seem to be able to reach the correct answer, hopefully someone out there can help me! A capacitor of capacitance 180pF is charged to a P.D of 12V and then discharged through a sensitive meter. This sequence of operations is repeated 250 times per second, what is the average current registered by the meter? The way I see it, the maximum charge on the capacitor is is 12*(180*10^-12) = 2.16*10^-9. The switch charges and discharged 250 times per second, so in a second the current goes from 0 to 2.16*10^-9 and then back down again to 0. I would therefore assume that the average current is the halfway point, so (2.16*10^-9)/2. Apparently this is not correct and I can not see how to find a valid answer. Any help would be much appreciated.