In the figure attached, the battery has a potential difference of 10 V and the five capacitors each have a capacitance of 20 µF. What is the excess charge on capacitor 2?(adsbygoogle = window.adsbygoogle || []).push({});

I go inside out from the capacitors in series [tex]C_2[/tex] and [tex]C_3[/tex]. My notation simply denotes the equivalent resistance depending on the type of connection (series/parallel).

[tex]C_{S1}= \left( \frac{1}{C_2} + \frac{1}{C_3} \right) ^{-1}[/tex]

[tex]C_{P1}= C_{S1} + C_4[/tex]

[tex]C_{S2}= \left( \frac{1}{C_{P1}} + \frac{1}{C_5} \right) ^{-1}[/tex]

[tex]C_{P2}= C_{S2} + C_1[/tex]

It also follows that

[tex]Q_2 = Q_3 = Q_{S1}[/tex]

[tex]V_4 = V_{S1}[/tex]

[tex]Q_5 = Q_{P1} = Q_{S2}[/tex]

[tex]V_1 = V_{S2}[/tex]

So, I get

[tex]Q_2 = Q_{S1} = V_{S1} C_{S1} = 1.0\bar{6} \times 10^{-4} \mbox{ C}[/tex]

which is wrong! Could anybody please help me find the mistake?

Any help is highly appreciated.

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# Homework Help: Capacitance problem

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