After the switches have been closed, in which circuit will the charge on the left hand capacitor increase? decrease? stay the same?
(1/Ceq) = (1/c1) + (1/c2)
q = cv
The Attempt at a Solution
Okay so, I figured if I solve the total voltage of each capacitor, and then use q=cv, using Ceq and the total voltage, then I would get my answer. However, my answers indicated that the charge decreases in every example, and this is supposedly the wrong answer. Can someone please help?
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