1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Capacitor and energy

  1. Sep 27, 2013 #1
    A capacitor consists of two closely spaced metal conductors of large area, separated by a thin insulating foil. It has an electrical capacity of 3000.0 μF and is charged to a potential difference of 87.0 V. Calculate the amount of energy stored in the capacitor.

    Calculate the charge on this capacitor when the electrical energy stored in the capacitor is 6.53 J.

    U= (1/2)C(dV^2)
    Q= C(dV)

    I found the first answer but for the 2nd part with the 6.53 J, I'm not getting the right answer.
    I figured I'd use U= (1/2)C(dV^2) and solve for C. Then plug C into Q= C(dV). dV is the same for both questions.

    U= (1/2)C(dV^2)
    2U/(dV^2)= C
    C= 1.72e-3 F

    Q= C(dV)= .14964 C
    That's not right answer though. What am I doing wrong?
  2. jcsd
  3. Sep 27, 2013 #2
    You already know C it is given by the question-> 3000.0 μF
    C is a constant not V; V will be different for second question.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted