(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A capacitor is charged to 1 coulomb; the capacitance is 8.00×10-5 farads. Then a switch is closed which puts the capacitor in a closed circuit with a resistor; the resistance is 8.60×10^{1}ohms. Calculate the charge on the capacitor after 4.00 milliseconds. (1 ms = 0.001 s)

2. Relevant equations

I=V/R

C=Q/V

3. The attempt at a solution

C=Q/V=8E-5 F=1/V V=12500 V

I=V/R=12500/86=145.348 A

145.348 C/S = .145348 C/mS

.145348*4=.5814 C transferred in that 4 milliseconds

1-.5814=.4186 C left

So the answer would be .4186 C I think but I'm getting an "Incorrect Answer" apparently

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# Homework Help: Capacitor Discharge problem

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