1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Capacitor Electron Transfer

  1. Feb 10, 2010 #1

    jacksonpeeble

    User Avatar
    Gold Member

    1. The problem statement, all variables and given/known data
    A capacitor has a capacitance of 2.56 10-8 F. In the charging process, electrons are removed from one plate and placed on the other plate. When the potential difference between the plates is 460 V, how many electrons have been transferred?


    2. Relevant equations
    q=CV
    Number of Electrons=q/e


    3. The attempt at a solution
    q=2.56*10^-6*460=1.1776*10^-5

    What is e? I assume this is a constant, but I don't have my book on me to find what it is exactly.
     
  2. jcsd
  3. Feb 10, 2010 #2

    jacksonpeeble

    User Avatar
    Gold Member

    Nevermind, e=1.6*10^-19, so the final answer is 7.36*10^13. Sorry for the premature post!
     
    Last edited: Feb 10, 2010
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Capacitor Electron Transfer
  1. Transfer of Electrons (Replies: 3)

  2. Transfer of electrons (Replies: 3)

  3. Electron Transfer (Replies: 2)

Loading...