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Capacitor Electron Transfer

  1. Feb 10, 2010 #1


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    1. The problem statement, all variables and given/known data
    A capacitor has a capacitance of 2.56 10-8 F. In the charging process, electrons are removed from one plate and placed on the other plate. When the potential difference between the plates is 460 V, how many electrons have been transferred?

    2. Relevant equations
    Number of Electrons=q/e

    3. The attempt at a solution

    What is e? I assume this is a constant, but I don't have my book on me to find what it is exactly.
  2. jcsd
  3. Feb 10, 2010 #2


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    Nevermind, e=1.6*10^-19, so the final answer is 7.36*10^13. Sorry for the premature post!
    Last edited: Feb 10, 2010
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