1. The problem statement, all variables and given/known data A capacitor has a capacitance of 2.56 10-8 F. In the charging process, electrons are removed from one plate and placed on the other plate. When the potential difference between the plates is 460 V, how many electrons have been transferred? 2. Relevant equations q=CV Number of Electrons=q/e 3. The attempt at a solution q=2.56*10^-6*460=1.1776*10^-5 What is e? I assume this is a constant, but I don't have my book on me to find what it is exactly.