1. The problem statement, all variables and given/known data A capacitor has a peak current of 240 μA when the peak voltage at 250 kHz is 2.7 V . Part A What is the capacitance? Part B If the peak voltage is held constant, what is the peak current at 500 kHz 2. Relevant equations Xc=1/wC Vc=IcXc 3. The attempt at a solution I rearranged equation 2 to solve for Xc = 2.7V/0.000240A = 11250 I then rearranged equation to to solve for C =1/wXc = 3.56x10-4 This is not correct. Why is this not correct and what is the proper way to go about solving it? Thank you. Correction: I re-did the second calculation and got 3.56x10-10F by properly converting kHz to Hz but it's still wrong.