- #1
BunDa4Th
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Two capacitors, C1 = 25 µF and C2 = 6.0 µF, are connected in parallel and charged with a 150 V power supply.
(a) Calculate the total energy stored in two capacitors.
energy stored = 1/2C(deltaV)^2 or Q^2/2C
I been doing this and its marking me wrong.
first i found both charges which is
Q = VC
C1 = 3750 uC
C2 = 900 uC
then i did
3750^2/2(25) = 281250
900^2/2(6) = 67500
i add both up and get 348750 J
It is saying my answer is incorrect and i did this problem 3 different way getting the same number.
does this look like a system error or is my number really off.
(a) Calculate the total energy stored in two capacitors.
energy stored = 1/2C(deltaV)^2 or Q^2/2C
I been doing this and its marking me wrong.
first i found both charges which is
Q = VC
C1 = 3750 uC
C2 = 900 uC
then i did
3750^2/2(25) = 281250
900^2/2(6) = 67500
i add both up and get 348750 J
It is saying my answer is incorrect and i did this problem 3 different way getting the same number.
does this look like a system error or is my number really off.