- #1
jena
- 74
- 0
Hi,
Question:
An uncharged capacitor is connected to a 24.0-V battery until it is fully charged, after which it is disconnected from the battery. A slab of paraffin is then inserted between the plates. what will now be the voltage between the plates?
I know that as long as the capacitor stays connect the battery, the voltage stays constant and equal to the battery, since its disconnected the charge will have nowhere to go. I also know from my reading that the capacitance increases because of the dielectric(paraffin), but the voltage decrease because of it.
After this I'm lost. Do I need the dielectric strength of the paraffin to help in this problem.
Thank You
Question:
An uncharged capacitor is connected to a 24.0-V battery until it is fully charged, after which it is disconnected from the battery. A slab of paraffin is then inserted between the plates. what will now be the voltage between the plates?
I know that as long as the capacitor stays connect the battery, the voltage stays constant and equal to the battery, since its disconnected the charge will have nowhere to go. I also know from my reading that the capacitance increases because of the dielectric(paraffin), but the voltage decrease because of it.
After this I'm lost. Do I need the dielectric strength of the paraffin to help in this problem.
Thank You