Two capacitors of capacitances 3μf and 6μf are charged to potentials of 2V and 5V respectively. These 2 charged capacitors are now connected in series.Find the charge and potential difference across each of the capacitors now.
The Attempt at a Solution
Q1= 6*10-6 Q2=3*10-5
Total charge Q= 36*10-6C
Net capacitance of combination in series.
1/Cs= 1/C1 + 1/C2
Potentital difference of system in series = Q/Cs
The problem I am facing is finding the charge on each capacitor. I don't think it can be the same as before because the potential differences across them definitely would have changed. And in rule, capacitors in series get the same charge. So does that mean the 36*10-6C splits equally between them? Or do they both have 36*10-6.C And for either, why?