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Capacitors and dielectrics

  1. Feb 25, 2015 #1
    1. The problem statement, all variables and given/known data

    You are building a parallel plate capacitor out of two square metal plates with side lengths of L and a thin piece of dielectric of thickness d and dielectric strength of Eb. The piece of dielectric will act as a means of separating the two metal plates. In terms of l, Eo(epsilon knot), k, d, Eb how much charge can the capacitor hold before it fails? With l = 10cm, d = .1mm and paper as a dielectric what is the capacitance of your capacitor? How much charge can the capacitor hold before it fails?


    2. Relevant equations

    eq1: C = EoL; L for a parallel-plate capacitor is = A/d

    with a dielectric completely filling the space between the plates:


    eq 2: C = kEo(A/d)
    eq 3: q = CV
    eq 4: V = E/d


    3. The attempt at a solution

    Using those equations I came up with:

    q = CV = (kEoL^2/d)(Eb/d) = EbkL^2Eo/d^2

    For the second part of the question with k = 3.5 and eq2 I come up with:

    C = 3.5(8.85x10^(-12))(.1^2/.0001) = 3.096 x 10^-9 F

    and for the final equation where Eb = 16 I said:

    q = 16(3.5)(.1)^2(8.85x10^(-12))/(.0001)^2
    = 4.96x10^(-4) C

    However, I made the assumption that E = Eb in eq3. If someone could check my work and tell me if I did this problem correctly that would be great, any help appreciated.
     
  2. jcsd
  3. Feb 26, 2015 #2

    ehild

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    Homework Helper
    Gold Member



    I do not understand what you mean with eq 1, and the last equation (eq 4) is wrong . Check.
     
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