Capacitors and electric field

In summary, the question involves calculating the electric field halfway between two pie pans that are 3.5 cm apart and the answer is the same because the electric field is constant between the plates.
  • #1
fwFAWFSERG
11
0
REVIEWING OLD TEST and.. don't understand why you use the full distance.

Homework Statement


pretty much there's a home made capacitor made by two pie pans 3.5 cm apart. V is given Q is given, the question asks:
calculate the electric field halfway between the plates

Homework Equations


dV=Ed


The Attempt at a Solution



you just simply plug in, but why is distance the full 3.5 cm and not half of that, as youre finding the field at a distance that is halfway between the plates? am i answering my own question and the E field is constant?
 
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  • #2
Yes, the electric field is uniform between the plates so it would be the same.
 
  • #3


There are a few things to consider when calculating the electric field between two plates of a capacitor. First, the distance between the plates is important because it affects the overall capacitance of the system. The closer the plates are together, the higher the capacitance will be. In this case, the distance of 3.5 cm is given and should be used in the calculation.

Secondly, the electric field between the plates is not constant. It is strongest near the edges of the plates and decreases as you move towards the center. However, if the distance between the plates is small compared to the size of the plates, the electric field can be considered approximately constant. In this case, the distance of 3.5 cm is small compared to the size of the plates and the electric field can be assumed to be constant.

Finally, when calculating the electric field halfway between the plates, it is important to remember that the electric field lines are perpendicular to the plates. This means that the electric field halfway between the plates will be at a right angle to the plates and will not be affected by the distance between the plates. Therefore, the full distance of 3.5 cm should be used in the calculation.

In conclusion, when calculating the electric field between two plates of a capacitor, it is important to consider the distance between the plates, the size of the plates, and the direction of the electric field lines. In this case, the full distance of 3.5 cm should be used in the calculation as it is small compared to the size of the plates and the electric field can be assumed to be constant.
 

1. What is a capacitor?

A capacitor is an electronic component that stores electric charge. It consists of two conductive plates separated by an insulating material called a dielectric. When a voltage is applied, one plate accumulates positive charge while the other accumulates negative charge, creating an electric field between the plates.

2. How does a capacitor work?

A capacitor works by storing energy in an electric field. When a voltage is applied, electrons from the negative plate are attracted to the positive plate, creating a potential difference between the plates. The electric field between the plates stores this energy, which can be released when the capacitor is discharged.

3. What is the unit of capacitance?

The unit of capacitance is farad (F), named after the English physicist Michael Faraday. One farad is defined as the amount of capacitance that can store one coulomb of charge with a potential difference of one volt between the plates.

4. How does the size and distance between plates affect capacitance?

The capacitance of a capacitor is directly proportional to the size of the plates and inversely proportional to the distance between them. This means that larger plates or a smaller distance between them will result in a higher capacitance, while smaller plates or a larger distance will result in a lower capacitance.

5. Can a capacitor store an infinite amount of charge?

No, a capacitor has a finite capacity and can only store a certain amount of charge before reaching its maximum voltage. If too much charge is applied, the capacitor can become damaged or fail. It is important to choose a capacitor with the appropriate capacitance for the desired application.

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