1. The problem statement, all variables and given/known data A capacitor has been charged by connecting it to a 24 V battery. How much work was done in charging this capacitor, when at the end of charging, its charge is 3 µC? a. 8 µJ b. 12 µJ c. 36 µJ *d. 74 µJ 2. Relevant equations W=E=Q2/2C=QV/2 3. The attempt at a solution W=E=QV/2=24V*3μC/2=36μJ The answer key says the answer is really 74μJ, but I dont know what I did wrong.