1. The problem statement, all variables and given/known data A capacitor is completely charged with 670 nC by a voltage source that had 200 V. What is its capacitance?==== 3.35×10-9 F 9(I got this y doing Q/V) The initial air gap of the capacitor above was 7 mm. What is the stored energy if the air gap is now 10 mm? Now this is the part with which I am stuck 3. The attempt at a solution I know that Energy = (1/2)CV^2 or QV/2, as well as Q^2/2C But the problem is, I dont know what steps should be done before i reach the last step for calculating the energy stored. Please help!