- #1

coldturkey

- 25

- 0

Two parallel plates of area 100cm^2 are given charges of equal magnitudes 8.9x10^-7 but opposite signs. The electric field within the dieletric material filling the space between the plates is 1.4x10^6 V/m.

a) Calculate the dielectric constant of the material. b) Determine the magnitude of the charge induced on each dielectric surface.

I have tried using: E = surface charge density/(dielectric constant * Epsilon0 (8.85*10^-12) but I get a dielectric material which has a lower dielectric constant than air.

I really need a formula to relate capacitance to electric field.

Any help would be much appreciated.