(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

so, we have a capacitor which has capacitance C1 and charge Q0. This capacitor is connected to a second one (capacitance C2) with initial charge Q=0. The capacitors are in a series fashion with no voltage source. What charge does each carry now? Also find the potential difference.

2. Relevant equations

I think we can use PE = Q^2/2C and Q=CV

3. The attempt at a solution

I thought of tackling the problem by using the fact that potential energy is constant. I know that some of the charge from the first resistor will transfer to the second.

So, because Q0 is the initial charge of the first capacitor, PE = Q0^2/2C1.

After some time, let Q2 be the charge which leaves the first capacitor and enters the uncharged capacitor. PE= (Q0-Q2)^2/C1 + Q2^2/C2.

I then equated the two of them. It seems that Q2= 2Q0/(C1+C2) but the correct answer should be the one without a 2. Does anyone know how to tackle this problem? thanks

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# Homework Help: CAPACITORS! help please

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