1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Capacitors in a simple network

  1. May 10, 2015 #1

    Suraj M

    User Avatar
    Gold Member

    1. The problem statement, all variables and given/known data
    Here's the question as it was given. WIN_20150510_213510.JPG

    we should find the effective capacitance across A and B,

    2. Relevant equations
    ##C_p = C_1 +C_2+...##
    ##\frac{1}{C_s} = \frac{1}{C_1} +\frac{1}{C_2} +....##

    3. The attempt at a solution
    Looking at the diagram i thought The capacitance should be zero.. shouldn't it be zero?
    because there is a wire directly connecting A and B.
    but the answer was given as 132 µF, that would happen if the 4 capacitors were in parallel, like this maybe WIN_20150510_213656.JPG
    then yes it should be 132µF.
    i still think that the answer to the original question is zero, could someone verify or correct me.
    Thank you
     

    Attached Files:

  2. jcsd
  3. May 10, 2015 #2

    NascentOxygen

    User Avatar

    Staff: Mentor

    Your first circuit is a short circuit so has no capacitance. The second one is 123uF.
     
  4. May 10, 2015 #3

    Suraj M

    User Avatar
    Gold Member

    You mean 132 µF
    Thank you, just needed to be sure.:)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Capacitors in a simple network
  1. Capacitors Network (Replies: 2)

  2. Network Capacitors (Replies: 7)

  3. Capacitor Network (Replies: 3)

  4. Capacitor Network (Replies: 3)

Loading...