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Capacitors in a simple network

  1. May 10, 2015 #1

    Suraj M

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    Gold Member

    1. The problem statement, all variables and given/known data
    Here's the question as it was given. WIN_20150510_213510.JPG

    we should find the effective capacitance across A and B,

    2. Relevant equations
    ##C_p = C_1 +C_2+...##
    ##\frac{1}{C_s} = \frac{1}{C_1} +\frac{1}{C_2} +....##

    3. The attempt at a solution
    Looking at the diagram i thought The capacitance should be zero.. shouldn't it be zero?
    because there is a wire directly connecting A and B.
    but the answer was given as 132 µF, that would happen if the 4 capacitors were in parallel, like this maybe WIN_20150510_213656.JPG
    then yes it should be 132µF.
    i still think that the answer to the original question is zero, could someone verify or correct me.
    Thank you

    Attached Files:

  2. jcsd
  3. May 10, 2015 #2


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    Staff: Mentor

    Your first circuit is a short circuit so has no capacitance. The second one is 123uF.
  4. May 10, 2015 #3

    Suraj M

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    Gold Member

    You mean 132 µF
    Thank you, just needed to be sure.:)
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