# Capacitors in a simple network

1. May 10, 2015

### Suraj M

1. The problem statement, all variables and given/known data
Here's the question as it was given.

we should find the effective capacitance across A and B,

2. Relevant equations
$C_p = C_1 +C_2+...$
$\frac{1}{C_s} = \frac{1}{C_1} +\frac{1}{C_2} +....$

3. The attempt at a solution
Looking at the diagram i thought The capacitance should be zero.. shouldn't it be zero?
because there is a wire directly connecting A and B.
but the answer was given as 132 µF, that would happen if the 4 capacitors were in parallel, like this maybe
then yes it should be 132µF.
i still think that the answer to the original question is zero, could someone verify or correct me.
Thank you

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2. May 10, 2015

### Staff: Mentor

Your first circuit is a short circuit so has no capacitance. The second one is 123uF.

3. May 10, 2015

### Suraj M

You mean 132 µF
Thank you, just needed to be sure.:)