# Capacitors in series homework

Instinctlol

logearav
V = q/c
so v = q/c + q/2c + q/3c
q/c(1+1/2+1/3)
q/c (11/6)
hope this helps

Instinctlol
So total V is (11/6)q/c ? Can you explain how that is V1?

logearav
So total V is (11/6)q/c ? Can you explain how that is V1?
I can't get you. Actually is 11/6 times the V

logearav
Capacitors are connected in series. So the effective capacitance is
1/Cs = 1/C + 1/2C + 1/3C
= 11/6C
Cs = 6C/11
Now substitute this value for C for the equation V = 11/6(Q/C) you ll get Q/C which is nothing but V or V1
Hope you got it now