Capacitors in series homework

[Instinctlol]

Homework Statement

http://session.masteringphysics.com/problemAsset/1006859/35/37016.jpg

Heres what I did
V_total=V₁+V₂/2+V₃/3

V_total=v₁+5/6 V_2,3

V_total -5/6 V_2,3 = 1/6 V₁

This is wrong, I want to know my mistake, please help. Thank you

 

[logearav]

V = q/c
so v = q/c + q/2c + q/3c
q/c(1+1/2+1/3)
q/c (11/6)
hope this helps

 

[Instinctlol]

So total V is (11/6)q/c ? Can you explain how that is V₁?

 

[logearav]

So total V is (11/6)q/c ? Can you explain how that is V₁?

I can't get you. Actually is 11/6 times the V

 

[logearav]

Capacitors are connected in series. So the effective capacitance is
1/C_s = 1/C + 1/2C + 1/3C
= 11/6C
C_s = 6C/11
Now substitute this value for C for the equation V = 11/6(Q/C) you ll get Q/C which is nothing but V or V1
Hope you got it now