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Capacitors in series

  1. Feb 8, 2012 #1
  2. jcsd
  3. Feb 8, 2012 #2
    V = q/c
    so v = q/c + q/2c + q/3c
    q/c(1+1/2+1/3)
    q/c (11/6)
    hope this helps
     
  4. Feb 8, 2012 #3
    So total V is (11/6)q/c ? Can you explain how that is V1?
     
  5. Feb 8, 2012 #4
    I can't get you. Actually is 11/6 times the V
     
  6. Feb 8, 2012 #5
    Capacitors are connected in series. So the effective capacitance is
    1/Cs = 1/C + 1/2C + 1/3C
    = 11/6C
    Cs = 6C/11
    Now substitute this value for C for the equation V = 11/6(Q/C) you ll get Q/C which is nothing but V or V1
    Hope you got it now
     
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