To capacitors are charged up with a potential difference of 24 volts, and then connected in series in a closed circuit. What is the final charge on each capacitor? C1 = 2,0*10^-6 F and C2 = 6,0*10^-6 F What I did was to compute the total capacitance of the system, and use that to figure out the charge on the capacitor, which would have to be the same on both of them. Or so I thought, the answer in my book says that the charge on each capacitor is just equal to what it would have been if it was just sitting by itself. Why won't the charges distribute themselves equally over both plates in this scenario?