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## Homework Statement

A 10.0 µF capacitor is fully charged across a 10.0 V battery. The capacitor is then disconnected from the battery and connected across an initially uncharged capacitor with capacitance C. The resulting voltage across each capacitor is 4.00 V. What is the value of C?

## Homework Equations

V= Q/C

## The Attempt at a Solution

My logic is that since the voltage changes, it is connected in series, so the charge is same. So I solved for Q for the first one and used it to plug solve for C for the second one. It is wrong, please help.