How do we derive the opposition to current flow (AC signal) due to capacitance without using complex numbers?(adsbygoogle = window.adsbygoogle || []).push({});

Is the capacitor's reactance a constant or an average?

If I were to measure the instantaneous voltage across a capacitor and the instantaneous current through it, shouldn't I get its reactance (according to Ohm's Law)?

Why do we get the reactance of the capacitor dividing the peak voltage by the peak current if they are always 90 degrees out of phase?

**Physics Forums - The Fusion of Science and Community**

# Capacitor's Reactance

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Capacitor's Reactance

Loading...

**Physics Forums - The Fusion of Science and Community**